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These are example questions from an aptitude test I found.?

This is a discussion on These are example questions from an aptitude test I found.? within the Aptitude Questions forums, part of the Freshers Zone category; 1. a=b+3(4-c) If b equals 5 and c equals 2, what is the value of a? 2. y=3(x+5)(x-2) Which of ...


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Aptitude Questions An aptitude is an innate ability to do a certain kind of work. Aptitudes may be physical or mental. All Aptitude related Information and Questions

 
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  #1  
Old 08-28-2007, 12:01 AM
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Default These are example questions from an aptitude test I found.?

1. a=b+3(4-c) If b equals 5 and c equals 2, what is the value of a?

2. y=3(x+5)(x-2) Which of the following formulas is equivalent to this one?

a. y=3x2+9x-30
b y=x2=3x-10
c. y=3x2+3x-10
d. y=3x2+3x-30

3. y=x+5 Which of the following choices represents the same relationship as demonstrated in this equation?

a y/5 x/10
10 15
15 20
20 25

b. Y is equivalent to the sum of a constant c and x, where c equals 5

c y=(x+20)/4

d. [table]

Please show steps to solving these problems.

Thanks In Advance
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  #2  
Old 08-28-2007, 12:03 AM
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1. when you substitute you get a= 5+3(4-2)
a= 5+3*2
a=11

2. a. First you must do the multiplication

y= 3(x^2-2x+5x-10)
y=3(x^2+3x-10)
y=3x^2+9x-30

3. b
I`m not really sure what you meant in a, but if I´m correct you meant that y=5 and x=10. Then, the only correct is 10/15
I couldn´t see the table either.
As for c, once you resolve it you get y=(x/4)+5. So, it`s not the same.
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  #3  
Old 08-28-2007, 12:16 AM
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Do your own homework!
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  #4  
Old 08-28-2007, 12:23 AM
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a) - Just substitute the numbers, so the problem becomes:-

5+ 3(4-2) - (Do the sum in brackets first then multiply the answer by 3 then add the 5)

b) - Y=3(x-5)(x-2) - Lose the brackets first by multiplyiny what's inside by eachother - (x-5)(x-2) - First multiply the xs, then the x in the first bracket by the 2 in the 2nd, then the minus 5 in the first bracket by the x in the 2nd, then the minus 5 in the 1st by the minus 2 in the 2nd. Add together the 4 terms and multiply by the 3 outside the brackets, and you should get to one of the options given.


3) - Should be fairly obvious from the options given - Y = x+5 so Y is 5 greater than X

Hope this helps
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Old 08-28-2007, 12:23 AM
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a) - Just substitute the numbers, so the problem becomes:-

5+ 3(4-2) - (Do the sum in brackets first then multiply the answer by 3 then add the 5)

b) - Y=3(x-5)(x-2) - Lose the brackets first by multiplyiny what's inside by eachother - (x-5)(x-2) - First multiply the xs, then the x in the first bracket by the 2 in the 2nd, then the minus 5 in the first bracket by the x in the 2nd, then the minus 5 in the 1st by the minus 2 in the 2nd. Add together the 4 terms and multiply by the 3 outside the brackets, and you should get to one of the options given.


3) - Should be fairly obvious from the options given - Y = x+5 so Y is 5 greater than X

Hope this helps
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  #6  
Old 08-28-2007, 12:23 AM
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1. a=b+3(4-c) If b equals 5 and c equals 2, what is the value of a?

a = 5 + 3(4-2) - substitute for b and c

2. y=3(x+5)(x-2) Which of the following formulas is equivalent to this one?

a. y=3x2+9x-30
b y=x2=3x-10
c. y=3x2+3x-10
d. y=3x2+3x-30

substitute x = 1 and see were u get the same answer for y
y=3(5+1)(1-2)

and do the same in a b c and d, put 1 in place of x

3. y=x+5 Which of the following choices represents the same relationship as demonstrated in this equation?

not sure
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  #7  
Old 09-08-2007, 10:10 PM
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thank you. it helped me alot
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