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Come take part in simple mathematics quiz.?

This is a discussion on Come take part in simple mathematics quiz.? within the Numerical Ability forums, part of the Freshers Zone category; Expand the following: Q1) (3 - a)(9 + 3a + a^2) Q2) (2x + 1)(x^2 - 3x - 4) Q3) ...


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  #1  
Old 08-28-2007, 02:02 AM
Jef Jef is offline
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Default Come take part in simple mathematics quiz.?

Expand the following:

Q1) (3 - a)(9 + 3a + a^2)
Q2) (2x + 1)(x^2 - 3x - 4)
Q3) (a + 2)(3a^2 - 5a + 6)
Q4) (p - 2q)(2p + 3q - 1)

Solve these questions correct with detailed workings and earn points!!!
The lucky person with the best answer will be voted as the "BEST ANSWER".
Voting of the best answer will take place after 12hours!!.
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  #2  
Old 08-28-2007, 02:05 AM
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Multiply everything by everything. That's the rule

27 + 9a + 3aa + (-9a) + (-3aa) + (-aaa).
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  #3  
Old 08-28-2007, 02:05 AM
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Q1) (3 - a)(9 + 3a + a^2)
= 3(9 + 3a + a^2) - a(9 + 3a + a^2)
= 27 + 9a + 3a^2 - 9a - 3a^2 - a^3
= 27 - a^3

Q2) (2x + 1)(x^2 - 3x - 4)
= 2x(x^2 - 3x - 4) + 1(x^2 - 3x - 4)
= 2x^3 - 6x^2 - 8x + x^2 - 3x - 4
= 2x^3 - 5x^2 - 11x - 4

Q3) (a + 2)(3a^2 - 5a + 6)
= a(3a^2 - 5a + 6) + 2(3a^2 - 5a + 6)
= 3a^3 - 5a^2 + 6a + 6a^2 - 10a + 12
= 3a^3 + a^2 - 4a + 12

Q4) (p - 2q)(2p + 3q - 1)
= p(2p + 3q - 1) - 2q(2p + 3q - 1)
= 2p^2 + 3pq - p - 4pq - 6q^2 + 2q
= 2p^2 - pq - 6q^2 - p + 2q

Interesting way to get people to do your homework for you.
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  #4  
Old 08-28-2007, 02:06 AM
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1........-a^3+27
2........2x^3-5x^2-11x-4
3........3a^3+a^2-4a+12
4........2p^2-p-pq+2q-6q^2

i hope these are correct !!
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  #5  
Old 08-28-2007, 02:06 AM
Yep Yep is offline
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I say f*ck it and grab a beer!
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