Can anyone solve this puzzle?

[Goanchu]

George was selling onions. one of his customers said that he would buy his whole stock.he asked george how many onions he had. as george could count only up to ten, he replied in the following manner
1) when i put the onions in heaps of 2 ,there is 1 onion left
2) when put them in heaps of 3 there are 2 left
3) when i put them in heaps of 4 there are 3 left
4) when i put them in heaps of 5 there are 4 left
5) when i put them in heaps of 6 there are 5 left
6) when i put them in heaps of seven there are none left
7) when i put them in heaps of eight there are 7 left

[markmai_2000@yahoo.com]

Unfortunately for the buyer, he will never know exactly how many onions there are, because if we listen to what george says, it gives us 7 equations with 8 unknowns, which means that there is are infinite solutions to this problem. The first 10 numbers that could work with what george said are:

119
959
1799
2639
3479
4319
5159
5999
6839
7679
,......

every one of these numbers finishes with a 9. is this a coincidence? No, because of 4): the last number can only be a 4 or a 9. But 4 is an even number and therefore cannot be the answer (see 1) ), so every solution MUST finish by a 9.

[sweetlikcandy1]

1) 21
2)32
3)43
4)54
5)65
6)70
7)87
Answer is 70

[Chamundi]

Sorry...I could not..Let me know the answer!

[sonu]

that ****er has nothing, he's just enjoying looking at morons like us trying hard to calculate lmao

[akshay k]

the question was too difficult for me to answer.